Hello,
I am using 20.4:1 Metal Gearmotor 25Dx65L mm HP 12V with 48 CPR Encoder. What is the internal pull-up resistor value in the encoder’s output A and output B pins?
I am trying to read the 5V-powered encoder with a 3.3V microcontroller, so I want to make a voltage divider circuit at the encoder’s output signals. It would be appreciated if somebody could provide any advice on what voltage divider resistor values are sufficient for this.
Thank you very much
Hello, Alexsy.
The encoder’s output lines are pulled-up to VCC with 10kΩ resistors.
Brandon
Hello, thank you for your response.
Is the PPR of the encoder 979.62 [counts per revolution] / 4 = 244.905 [pulses per revolution]?
Right, the 979.62 CPR of the gearbox’s output shaft mentioned on the 20.4:1 Metal Gearmotor 25Dx65L mm HP 12V with 48 CPR Encoder product page is counting low-to-high and high-to-low transitions of both encoder channels together. So, if you are only considering a full pulse (e.g. a low-to-high transition followed by a high-to-low transition) of a single output signal, then it would be 244.905 pulses per revolution.
Brandon
Thank you!
