I’m looking to use a D24V22F5 regulator with a 12V acid lead battery in a car on the Vin. It needs to have a low voltage cut-off function, to prevent the battery from being fully drained.
I heard that a simple voltage divider could be used such that when the battery falls below 12V, the output voltage from the voltage divider going into the enable pin is <1V, so it pulls the enable pin low and the regulator is disabled.
Can it be as simple as that? I have some concerns:
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Do I need to worry about hysteresis, or does the D24V22F5 take care of that?
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Some different regulators specify they turn off at an enable pin voltage of, e.g. 0.6V, and won’t turn on again until the enable pin voltage rises to a higher level, e.g. 0.8V. Does the D24V22F5 do something similar? All the description seems to say is that it’s disabled when the enable pin is driven under 1V.
Many thanks for reading, I hope this can be answered.
Paul